Probability of throwing 2 dices 1,000,000 times

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on December 22, 2011
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Probability of throwing 2 dices 1,000,000 times

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One comment

  • Lucas Fehlau says:

    I admire your interest for this, but the probability distribution for two dice can be easily calculated by Laplace’s law.
    It states that the probability of an event happening is equal to the ratio of how many times it happens, over all the possible results.
    Given that, there are 36 possible ways 2 dice can result (6*6), and you can only get a:
    2, by getting 1 and 1 (1/36 chance)
    3, 1,2;2,1 (2/36=1/18)
    4: 2,2;1,3;3,1 (3/36=1/12)
    5: 1,4;2,3;3,2;4,1 (4/36=1/9)
    6: 1,5;2,4;3,3;4,2;5,1 (5/36)
    7: 1,6;2,5;3,4;4,3;5,2;6,1 (6/36=1/6)
    8: similar to before, 5/36
    9:1/9
    10:1/12
    11:1/18
    12:1/36
    Still, the linear fashion that it has in the graph is curious. I’m used to the normal distribution.

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